Question

the sum of digits of 2digit no. is 11 if the no. obtained by reversing the digit is 9 less than the original no find the no.​

Answer 1

the no. is 65

hope it helps u

Answer 2

Answer:

let the numbers be x and y

CASE 1

∴ x +y=11----------------------------1

CASE 2

let original number =10x+y ( where x is at tens place and y at ones place)

∴10x+y-9=10y+x

10x -x+y-10y=9

9x-9y=9

x-y=1--------------------------------2

FROM EQUATION 1 AND 2

x+y=11

x-y=1

2x=12

x=6

∴ y=5

ORIGINAL NUMBER= 10(6)+5=65

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