Math, asked by vanibattu, 7 months ago

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Answered by battuadityarao
1

Answer:

\huge\bold\red{ANSWER}

Step-by-step explanation:

→   \large{\underline{\rm{\red{SOLUTION :}}}}

\implies \sf \blue{\frac{sin20^o}{cos20^o}+4sin20^o}

\implies \sf \green{\frac{sin20^o+2(2sin20^ocos20^o)}{cos^o}}

\implies \sf \yellow{\frac{sin20^o+2sin40^o}{cos20^o}}

\implies \sf \orange{\frac{sin20^o+4sin(60^o-20^o)}{cos20^o}}

\implies \sf \pink{\frac{sin20^o+2(sin60^ocos20^o-cos60^osin20^o)}{cos20^o}}

\implies \sf \purple{\frac{sin20^o+2(\frac{\sqrt{3}}{2} cos20^o-\frac{1}{2} sin 20^o)}{cos20^o}}

\implies \sf \violet{\frac{sin20^o+\sqrt{3}cos20^0-sin20^0}{cos20^o}}

\implies \sf \brown{\frac{\sqrt{3}cos20^o}{cos20^o}}

\implies \sf \boxed{\sqrt{3}}

\sf {Hope\:it\:helps\:you}

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