#Quality Question
@Sets
A survey shows that 63% of Americans like cheese whereas 76% like Apples.
If x percent of Americans like both is and apples then . . .
1) x = 39
2)x = 63
3)39 ⩽ x ⩽63
4)None of these
Explanation Needed.
Answers
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☆ Answer :
Option 3) 39 ⩽ x ⩽63
___________________________
☆ Given :
A Survey Concluded :-)
%of Americans who like CHEESE = 63%
% of Americans who like APPLES = 76%
% of Americans who like BOTH = x %
___________________________
☆ To Find :
% of American who like both i.e. value of x
___________________________
☆ Solution :
Let A and B denote the set of Americans who like Cheese and Apple respectively.
n(A) = 63 and n(B) = 76
According to De-Morgan's Law
n(A U B ) = n(A) + n(B) - n(A∩B)
⟹ n(A U B ) = 63 + 76 - n(A ∩ B)
⟹ n(A ∩ B) = 139 - n(A U B)
But, n(A U B) ⩽ 100
⟹ -n(A U B) ⩾ -100
⟹ 139 - n(A U B) ⩾ 139 - 100 = 39
⟹ 39 ⩽ n(A ∩ B) . . . (i)
Again ,
A ∩ B ⊆ A and A ∩ B ⊆ B
∴ n(A ∩ B) ⩽ n(A) = 63
and n(A ∩ B) ⩽ n(B) = 76
∴ n(A ∩ B) ⩽ 63 . . . (ii)
Combining eq (i) And (ii)
39 ⩽ n(A ∩ B) ⩽ 63
Soluťíòñ
Let Sets be such as
P = Americans who like Cheese
and
Q = Americans who like Apple
Accordingly,
n(P) = 63
and
n(Q) = 76
Now We know that ,
n(P U Q ) = n(P) + n(Q) - n(P∩Q) (De Morgan's Law)
n(P U Q ) = 63 + 76 - n(P ∩ Q)
n(P ∩ Q) = 139 - n(P U Q)
Also n(P U Q) ⩽ 100 (subset can exceed total no.present)
-n(P U Q) ⩾ -100 (while multiplying with -ve >>Sign of inequality changes )
139 - n(P U Q) ⩾ 139 - 100 = 39
∴ 39 ⩽ n(P ∩ Q)
Now ,
We Know
P ∩ Q ⊆ P and P ∩ Q ⊆ Q
(General Laws of Set Theory)
So,
n(P ∩ Q) ⩽ n(P) = 63
and n(P ∩ Q) ⩽ n(Q) ⩽ 76
∴ n(P ∩ Q) ⩽ 63
Both conditions Simultaneously concludes
39 ⩽ n(P ∩ Q) ⩽ 63
So,
39 ⩽ x ⩽63
Hence option 3 is correct.