Math, asked by guilherme020803, 5 months ago

quantos termos tem a sequência(4,7,10...262)

Answers

Answered by VIGYAS
3

Answer:

an = a1 + (n - 1)r

157 = 4 + (n - 1) . (7 - 4)

157 = 4 + (n - 1) . 3

157 = 4 + 3n - 3

157 = 3n + 1

157 - 1 = 3n

156 = 3n

3n = 156

n = 156/3

n = 52 termos

resposta: essa p.a tem 52 termos.

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