Question

qudratic equation maths ​

Answer 1

Answer:

$x = \frac{ - b + - \sqrt{b ^{2} 4ac} }{2a} \\ once \: in \: standard \: form \: the \: original \: equation \: and \: plug \: them \: into \: the \: quadratic \: formula \: \\ x^{2} + 7x - 8 = 0 \\ a = 1 \\ b = 7 \\ c = - 8 \\ x = \frac{ - 7 \: + - \: \sqrt{ {7 - 4.1( - 8)}^{2} } }{2.1} \\ x = \frac{ - 7 + - 9}{2} \\ x ^{2} = \frac{ - 7 + 9}{2} \: \frac{ - 7 - 9}{2} \\ sol \: - > \: x = 1 \\ x = - 8$

Answer 2

{\__/}

(• ◡ • )

/<❤>✨ANSWER✨

We have formula for solving quadratic equation

$a {x}^{2} + bx + c = 0$

$➠ \: x = \frac{b + - \sqrt{ {b}^{2} } - 4ac}{2a}$

$once \: in \: standard \: form \: \\ the \: original \: equation \: and \: \\ plugthemin \: to \: the \: quadratic \: \: \\ formula$

$➠ {x}^{2} - 7x + 8 = 0$

a ➪ 1

b ➪ 7

c ➪ -8

$➠ \: \frac{ - 7 + - \sqrt{7 - 4.1 {( - 8)}^{2} } }{2.1}$

$➠ \: x \: = \frac{- 7 + - 9}{2}$

$➠ \: x \: = \: \frac{ - 7 + 9}{2} \: \: \frac{ - 7 - 9}{2}$

$➠ \: x = \frac{ - 2}{2} \: \: \frac{ - 12}{2}$

$➠x = - 1 \: and \: - 8$