qudratic equations by completeing the square method xsquare+2x-5=0
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step 1 divide the equation by its leading cofficent
step 2 then convert it in to a factorise form by adding or subtracting the required thing
step 3 then solve the equation care fully you will get the answer
step 2 then convert it in to a factorise form by adding or subtracting the required thing
step 3 then solve the equation care fully you will get the answer
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x^2 + 2x -5
(x +1)^2 -5 -1 = (x +1)^2-6
In perfect square method we take a number with x in brackets such that 2ab obtained from (a + b)^2 is equal to the term with x having power 1
Here we want 2ab to be equal to 2x
Therefore we take 1 with x so that 2 × x × 1 = 2x and then we subtracs its square that is 1 square =1 outside brackets to eliminate it
Hope it helps
Thank u★★★
# ckc
Plz mark brainiest if correct
(x +1)^2 -5 -1 = (x +1)^2-6
In perfect square method we take a number with x in brackets such that 2ab obtained from (a + b)^2 is equal to the term with x having power 1
Here we want 2ab to be equal to 2x
Therefore we take 1 with x so that 2 × x × 1 = 2x and then we subtracs its square that is 1 square =1 outside brackets to eliminate it
Hope it helps
Thank u★★★
# ckc
Plz mark brainiest if correct
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