Qudratic polynomial 2x2-3x +1 has zeroes α and β.now form a qudratic polynomial whose zeroes are 3α and 3β.
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2x²-3x+1
by finding the zeroes,
we get x=1 and 1/2
i.e.α =1 and β=1/2
next condition,
3α =3*1=3
3β=3*1/2=3/2
to form quadratic polynomial,we have to use this formula
x²-(α+β)x+αβ
implies
x²-(3α+3β)x+3α*3β
x²-(3+3/2)x+3*3/2
x²-((6+3)/2)x+3*3/2
x²-(9/2)x+9/2
when we multiply by 2 we get,
x²-9x+9
HOPE IT HELPS YOU
PLS MARK IT BRAINLIEST
Thank you.
by finding the zeroes,
we get x=1 and 1/2
i.e.α =1 and β=1/2
next condition,
3α =3*1=3
3β=3*1/2=3/2
to form quadratic polynomial,we have to use this formula
x²-(α+β)x+αβ
implies
x²-(3α+3β)x+3α*3β
x²-(3+3/2)x+3*3/2
x²-((6+3)/2)x+3*3/2
x²-(9/2)x+9/2
when we multiply by 2 we get,
x²-9x+9
HOPE IT HELPS YOU
PLS MARK IT BRAINLIEST
Thank you.
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