Question

QUE 1) Rohit borrowed Rs 30,000 from his friend Rahul at 12% p.a. simple interest. He further lends it to his friend Ankit at the same rate but compounded annually. Find the gain after 2 years.​

Answer 1

Step-by-step explanation:

Given-:

• Rohit borrowed Rs 30,000 from his friend Rahul at 12% p.a. simple interest. He further lends it to his friend Ankit at the same rate but compounded annually. Find the gain after 2 years?

To find-:

• Principal = Rs 20000
• Rate = 12

• Time = 2 yrs, since we know that,

• S.l=pxrxt/100

• =20000 × 12 × 2 / 100 = Rs 4800

• Amount harish has return to his friend at simple interest

• A1 = 20000 + 4800 = Rs 24800 according to second statement:

• he lent it to amit at the same rate of interest and time but compounded annually.

• p = 20000, t = 2 yrs, r = 12 %

Find the Amount:

$amount = p [1 + (r/100) ]^t$

$=20000 [1+(12/100)]^2$

$= 20000 (112/100)^2$

Next step-:

$=20000x (112/ 100 ) × ( 112/100) XA2 = 25088$

Find the gain :

• Gain = A2 - A1 = 25088 - 24,800

• Gain = Rs 288

Therefore,

His gain after 2 years:-

$2 years = Rs 288$

Required answer:-

• Gain = Rs288

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Answer 2

Step-by-step explanation:

Rohit borrowed Rs 30,000 from his friend Rahul at 12% p.a. simple interest. He further lends it to his friend Ankit at the same rate but compounded annually. Find the gain after 2 years?

To find-:

Principal = Rs 20000

Rate = 12

Time = 2 yrs, since we know that,

S.l=pxrxt/100

=20000 × 12 × 2 / 100 = Rs 4800

Amount harish has return to his friend at simple interest

A1 = 20000 + 4800 = Rs 24800 according to second statement:

he lent it to amit at the same rate of interest and time but compounded annually.

p = 20000, t = 2 yrs, r = 12 %

Find the Amount: