Question

Que 15. 4x² + 4 bx - (a^2+b^2)=0​

Answer 1

Answer:

x = -1 + √{1 - (a^2+b^2)} / 2 , -1 - √{1 - (a^2+b^2)} / 2

Step-by-step explanation:

By putting the formula of quadratic equation,

x = -b +- √(b^2 - 4ac) / 2a

In this problem,

a = 4

b = 4

c = (a^2+b^2)

so,

x = -4 + √{4^2 - 4*4*(a^2+b^2)} / 2*4

= -4 + √ [16 {1 - (a^2+b^2)}] / 8

= -4 + 4[√{1 - (a^2+b^2)}] / 8

= -1 + √{1 - (a^2+b^2)} / 2 (dividing by 4)

or

x = -1 - √{1 - (a^2+b^2)} / 2