Question

Que 3) Solve the following.
1) Find SI when P= 5000, R= 8% and T = 2 years.​

Answer 1

${ \underbrace{ \text{Answer:}}}$

❃Formula used:

$\bold{S.l= \frac{P×R×T}{100} }$

❃Solution:

Given,

Principal= Rs.5000

Rate= 8%

Time= 2year

Now,

$\bold{S.I= \frac{50 \cancel{00 }\times 8 \times 2}{1 \cancel{00} }}$

$= > \bold{S.I=50 \times 8 \times 2}$

$= > \bold{S.I=800}$

Therefore, The value of simple Interest is Rs.800

Answer 2

Given : Principal (P) = 5000, Rate (R) = 8% and Time (T) = 2 years

Need To Find : Simple Interest ( S.I ) .

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❍ The Formula for Simple interest ( S.I ) is given by :

$\underline {\frak{ \dag As,\: We\:know\:that\::}}$

$\qquad \qquad \underline {\boxed { \sf{ Simple \:Interest \:= \dfrac{P \times R \times T }{100} }}}$

⠀⠀⠀⠀⠀Here P is the Principal in Rs. , R is the Rato of Interest in % and T is the time in yrs .

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$\qquad \qquad \qquad:\implies \sf {Simple \:Interest \:: \dfrac{5000 \times 8 \times 2 }{100} }$

$\qquad \qquad \qquad:\implies \sf {Simple \:Interest \:: \dfrac{50\cancel {00} \times 8 \times 2 }{\cancel {100}} }$

$\qquad \qquad \qquad:\implies \sf {Simple \:Interest \::50 \times 8 \times 2 }$

$\qquad \qquad \qquad:\implies \sf {Simple \:Interest \:: 100 \times 8 }$

⠀⠀⠀⠀⠀$\underline {\boxed{\pink{ \mathrm {  Simple \:Interest \:= Rs.\: 800}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm { Simple \:Interest \:(S.I) \:on\:given\:values \:is\:\bf{Rs\: 800}}}}$

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