Chemistry, asked by chocogirl92, 9 months ago

Que :-- calculate the EMF of a cell which is represented as follows:

plzzz solve it soon ...

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Answered by doraemonfan

3

Explanation:

EmF of cell =Ecathode-Eanode

=0.80-(-0.25)

=0.80+0.25

=1.05Volt

in cathode there is reduction so Ag is cathode

in anode there is oxidation so Ni Is anode

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