Question

Que. Calculate the no. Of photon of light required to dissociate 1 mol cl2 in cl atom if bond energy of cl cl bond is 1.240 kj/mol ,lambda =2000angstrong​

Answer 1

Answer:

Explanation:

For calculation of longest wavelength of light that can break Cl-Cl bond can be found by using Formula E = Nhc/λ

where h= planck's constant,

c = speed of light,

λ = wavelength of light,

n = no of molecules (no. of photon required)

and

NA= Avogadro's Number

λ = n×3×10 8 / 1.240×10 3 = 2000 × 10 -10

2000 × 10 -10 = n×3×10 8 / 1.240×10 3

n = 2 × 10 -7 × 1.240 × 10 3 / 3 × 10 8

n = 0.8266 × 10 -12

n = 8.27 × 10 - 13 photon

Answer 2

Answer:

The number of photons of light required to dissociate one mole of Cl₂ is equal to 124.8 × 10¹⁹.

Explanation:

Given, the bond energy of the Cl-Cl bond, E = 1.240 KJ/mol

The wavelength of light, λ = 2000Å = 2000×10⁻¹⁰m

The dissociate 1 mol of Chlorine gas:- Cl₂  + hν  $\longrightarrow$   2Cl

The velocity of light, c = 3 × 10⁸ m/s

The Plank's constant, h = 6.626 × 10⁻³⁴Js

We know that, E = hν

$E=h\frac{c}{\lambda}$

Substitute the value of h, c and  λ in above equation:

$E= (6.626\times 10^{-34}Js)\times\frac{3\times 10^{8}m/s}{2000\times 10^{-10}m}$

$E= 0.00993\times 10^{-16}J$

The number of photons = Total bond energy/Energy of one photon

Number of photons $=\frac{1.240\times 10^3}{0.00993\times 10^{-16}}$ = 124.8 × 10¹⁹ photons.

Therefore, the number of photons of light required to dissociate one mole of Cl₂ is equal to 124.8 × 10¹⁹.

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