Math, asked by 1Ayush786, 11 months ago

Que. for genius mathematicians...​

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Answered by spiderman2019
0

Answer:

5

Step-by-step explanation:

2Sin²38 + 3 + 2Sin²52 / 3Cosec²17 - 2 - 3Tan²73

= 2Sin²(90 - 52) + 3 + 2Sin²52/3Cosec²(90-73) - 2 - 3Tan²73

= 2Cos²52+3+2Sin²52/3Sec²73 - 3 Tan²73 - 2

= 2(Cos²52+ Sin²52) + 3 /3 (Sec²73 - Tan²73) - 2

= 5/1

= 5.

Answered by Anonymous
0

Answer:

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