Hindi, asked by ItzCandy2, 9 months ago

Que : In Figure, ABC and ABD are two triangles on the same base AB. If line- segment CD is bisected by AB at O, show that: ar(ABC) = ar(ABD).

Answers

Answered by Anonymous

Answer:

In ΔABC, AO is the median. (CD is bisected by AB at O)

∴ ar(AOC) = ar(AOD) — (i)

also,

ΔBCD, BO is the median. (CD is bisected by AB at O)

∴ ar(BOC) = ar(BOD) — (ii)

Adding (i) and (ii),

We get,

ar(AOC) + ar(BOC) = ar(AOD) + ar(BOD)

⇒ ar(ABC) = ar(ABD)

___________________

Hope it will be helpful :)

Answered by Anonymous

$<body bgcolor="r"><font color="yellow">$

$\huge {\bigstar {\red {\underbrace {\overbrace {\underline {\overline {\purple {\mathfrak {Answer}}}}}}}}}$

$<marquee scrollamount=1300>❤❤❤✌✌✌</marquee>$

In the given ∆ABC , AO is the median (as CD is bisected by AB at O)

So , ar (AOC) = ar (AOD) -- (i)

Similarly ,

In the given ∆BCD , BO is the median (as CD is bisected by AB at O)

So , ar (BOC) = ar (BOD) -- (ii)

Now , from eq. (i) & (ii) , we get

ar (AOC) + ar (BOC) = ar (AOD) + ar (BOD)

=>ar (ABC) = ar (ABD)

$<marquee>$ •●Hope it helps you●•

Previous Question

Next Question