ques 118 Aakash Institute East with feet 10 metre per second has another queue movue best with the speed 15 metre per second is a moment equal to zero the separation between the class is hundred metres a separation between them at the moment equal to 2 is
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initial separation between them = 100 m
speed of approach of them towards each other = 10+15 = 25m/s
the distance between them reduces at 25 m/s
so separation between them at t = 2 s : 100 m - 2s * 25 m/s = 50 m
speed of approach of them towards each other = 10+15 = 25m/s
the distance between them reduces at 25 m/s
so separation between them at t = 2 s : 100 m - 2s * 25 m/s = 50 m
Anshul201:
is this the only answer?
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