Math, asked by sheetaljoshi481, 11 months ago

Ques- Present age of father is 42 years and that of his son is 14 years. Find the ratio of
[A]- Present age of father to the present age of son.
[B]- age of the father to the age of son, when son was 12years old.
[C]- Age of father after 10 years to the age of son after 10 years.
[D]- Age of father to the age of son when father was 30 years old.​

Answers

Answered by Anonymous
3

 \huge \bold \red {Answer:-}

[A] The ratio of the age of father and of his son -

=  \huge \frac {42}{14}

=  \huge \frac {3}{1}

= 3:1 is the ratio.

[B] We know that son's age is 14 years now, so two years ago it was 12 years and the ratio of father's age to the sons age is 3:1 so,

12*3 = 36

So father's age is 36 years and son's age is 12 years.

Ratio -  \huge \frac {36}{12}

= 3:1 or 36:12 is the ratio.

[C] age of father after ten years will be 42 + 10 = 52 years and age is son after ten years will be 14+10= 24 years ,so

 \huge \frac {52}{24}

= 3:1 or 52:24 is the ratio.

[D] When father was 30 years old means when it was 42-30 = 12 years ago so the age of the son 12 years ago would be 14-12 = 2 years , so

 \huge \frac {30}{2}

= 15:1 or 30:2 is the ratio.

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