Math, asked by mounimounikamr898456, 9 months ago

QueSCIUIT 9.
The average weight of 9 boys in a class is 27 kg and the median of their weights is 30 kg. The weight of the heaviest boy is 12 kg more than two times the weight of
the lightest boy. The weights of all the 9 boys are integral values and the lightest and heaviest boys are exactly one each in the class. What is the maximum possible
range of the weights of these 9 boys?
Pick ONE option
A) 22
B) 28
C) 30
D) 32​

Answers

Answered by amitnrw
0

Given :  The average weight of 9 boys in a class is 27 kg and the median of their weights is 30 kg The weight of the heaviest boy i 12 kg more than two times the weight of the lightest boy. The weights of all the 9 boys are integral values and the lightest and heaviest boys are exactly one each in the class.

To find : What is the maximum possible range of the weights of these 9 boys

Solution:

Weight of lightest   = a

Weight of heaviest = 2a + 12

Range = a + 12

Average weight = 27

9 students

Total Weight = 9 * 27 = 243  kg

Median Weight = 30 kg

To have maximum range a should be maximum  and to have a  maximum

( weight of 3 students between lighest & 30 kg should be minimum )

& ( weight of 3 students between 30 kg & heaviest should also be minimum )

as lighest is exactly one

hence a + 1  can be minimum weight of 3 students  

Let say weights are  to have maximum range

a   ,  a+1,  a+1 a+1  , 30  , 30 , 30 , 30    ,2a + 12

Total weight =  6a + 123

6a + 123 = 243

=> 6a  = 120

=> a = 20

2a + 12 = 52

20 , 21 , 21 , 21 , 30 , 30 , 30 , 30 , 52  are the weight of 9 students

Maximum possible range  =  52 - 20  = 32

option D is correct

32 is the maximum possible range

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Answered by akaysingh34
0

Answer:

d is correct 32 will be the answer

mark me as brainliest

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