quesssssssssssskkkkkkkkkk!
Attachments:
Answers
Answered by
0
hlooo mate ur ans ....❤
Attachments:
Anonymous:
are mai uss baat sai kuvch nhi kh rhi hu
Answered by
3
x(t) = A cos(ωt + Φ)
1 = A cos(ω × 0 + Φ) = A cos Φ
A cosΦ = 1 …(i)
Velocity, v= dx/dt
ω = –A ωsin(ωt + Φ)
1 = –A sin(ω × 0 + Φ) = –A sin Φ
A sin Φ = -1 …(ii)
Squaring and adding equations (i) and (ii), we get:
A2 (sin2 Φ + cos2 Φ) = 1 + 1
A2 = 2
∴ A = √2 cm
Dividing equation (ii) by equation (i), we get:
tanΦ = -1
∴ Φ = 3π/4 , 7π/4,……
SHM is given as:
x = Bsin (ωt + α)
Putting the given values in this equation, we get:
1 = Bsin[ω × 0 + α] = 1 + 1
Bsin α = 1 …(iii)
Velocity, v = ωBcos (ωt + α)
Substituting the given values, we get:
π = πBsin α
Bsin α = 1 …(iv)
Squaring and adding equations (iii) and (iv), we get:
B2 [sin2 α + cos2 α] = 1 + 1
B2 = 2
∴ B = √2 cm
1 = A cos(ω × 0 + Φ) = A cos Φ
A cosΦ = 1 …(i)
Velocity, v= dx/dt
ω = –A ωsin(ωt + Φ)
1 = –A sin(ω × 0 + Φ) = –A sin Φ
A sin Φ = -1 …(ii)
Squaring and adding equations (i) and (ii), we get:
A2 (sin2 Φ + cos2 Φ) = 1 + 1
A2 = 2
∴ A = √2 cm
Dividing equation (ii) by equation (i), we get:
tanΦ = -1
∴ Φ = 3π/4 , 7π/4,……
SHM is given as:
x = Bsin (ωt + α)
Putting the given values in this equation, we get:
1 = Bsin[ω × 0 + α] = 1 + 1
Bsin α = 1 …(iii)
Velocity, v = ωBcos (ωt + α)
Substituting the given values, we get:
π = πBsin α
Bsin α = 1 …(iv)
Squaring and adding equations (iii) and (iv), we get:
B2 [sin2 α + cos2 α] = 1 + 1
B2 = 2
∴ B = √2 cm
Similar questions