Question

Question 1.15: Consider a uniform electric field E = 3 × 10 3 îN/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?

Class 12 - Physics - Electric Charges And Fields Electric Charges And Fields Page-47

Answer 1

Hey mate!

Here's your answer!!

Given:

E = 3000 N/C

a = 10 cm

(a) Flux = E.ΔS

= 3000 x 100 x 1/10000

= 30 Nm2/C

(b) Flux = E.ΔS.cos30o = 25.98 Nm2/C.

$hope \: it \: helps \: you.$

Answer 2

Answer:

B) flux =magnitude of electric field (E) ×A×cos theta(Theta =60°)

Explanation:

E=3×10^3 A=0.01m

Substitute this we get

Flux =15NC^-1m^2