Question 1.3: Check that the ratio ke 2 /G memp is dimensionless. Look up a Table of Physical Constants and determine the value of this ratio. What does the ratio signify?
Class 12 - Physics - Electric Charges And Fields Electric Charges And Fields Page-46
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The ratio of electrostatic force to the gravitational force between an electron and proton which is separated r distance from each other is given by
Fe/Fg = {Ke.e/r²}/{GMeMp/r²} = Ke²/GMeMp
∵Ratio of forces is dimensionless . Means, Fe/Fg is dimensionless.
∴ Ke²/GMeMp also will be dimensionless .
Hence, the ratio of Ke²/GMeMp is dimensionless .
Here, K = 9 × 10⁹ Nm²/C²
e = 1.6 × 10⁻¹⁹ C
G = 6.67 × 10⁻¹¹ Nm²/Kg²
Me = 9.1 × 10⁻³¹ Kg
Mp = 1.67 × 10⁻²⁷ Kg
Now, Ke²/GMeMp = {9 × 10⁹ × (1.6 × 10⁻¹⁹)²}/{6.67 × 10⁻¹¹ × 9.1 × 10⁻³¹ × 1.67 × 10⁻²⁷}
= 0.23 × 10⁴⁰ = 2.3 × 10³⁹
Fe/Fg = {Ke.e/r²}/{GMeMp/r²} = Ke²/GMeMp
∵Ratio of forces is dimensionless . Means, Fe/Fg is dimensionless.
∴ Ke²/GMeMp also will be dimensionless .
Hence, the ratio of Ke²/GMeMp is dimensionless .
Here, K = 9 × 10⁹ Nm²/C²
e = 1.6 × 10⁻¹⁹ C
G = 6.67 × 10⁻¹¹ Nm²/Kg²
Me = 9.1 × 10⁻³¹ Kg
Mp = 1.67 × 10⁻²⁷ Kg
Now, Ke²/GMeMp = {9 × 10⁹ × (1.6 × 10⁻¹⁹)²}/{6.67 × 10⁻¹¹ × 9.1 × 10⁻³¹ × 1.67 × 10⁻²⁷}
= 0.23 × 10⁴⁰ = 2.3 × 10³⁹
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Explanation:
The given ratio is
Where,
and it's unit is
Masses of Electron and proton
Their unit is kg
e = electric charge
it's unit is C
Permittivity of free space
it's unit is
Therefore, unit of given ration,
=
Hence the given ratio is Dimensionless
Hence the numerical value of given ratio is
This is the ratio of electric force to the gravitational force between a proton and an electron, keeping distance between them constant
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