Question

Question 1.9: A system has two charges qA = 2.5 × 10 −7 C and qB = −2.5 × 10 −7 C located at points A: (0, 0, − 15 cm) and B: (0, 0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system?

Class 12 - Physics - Electric Charges And Fields Electric Charges And Fields Page-46

Answer 1

Solution:-

given by:-

》At A, amount of charge, qA = 2.5 × 10−7C

》At B, amount of charge, qB = −2.5 × 10−7 C

》Total charge of the system,

》q = qA + qB = 2.5 × 10-7 C − 2.5 × 10−7 C = 0

》Distance between two charges at points A and B,

》d = 15 + 15 = 30 cm = 0.3 m

》Electric dipole moment of the system is given by,

》p = qA × d = qB × d = 2.5 × 10−7 × 0.3 = 7.5 × 10−8 C m along positive z-axis

》Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive −axis.☆

Answer 2

Hey mate!

Here's your answer!!

Both the charges can be located in a coordinate frame of reference as shown in the given figure in the attachment.

At A, amount of charge, qA = 2.5 × 10−7C
At B, amount of charge, qB = −2.5 × 10−7 C
Total charge of the system,
q = qA + qB
= 2.5 × 107 C − 2.5 × 10−7 C
= 0

Distance between two charges at points A and B, d = 15 + 15 = 30 cm = 0.3 m
Electric dipole moment of the system is given by, p = qA × d = qB × d
2.5 × 10−7 × 0.3
7.5 × 10−8 C m along positive z-axis.

Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive z−axis.

$hope \: it \: helps \: you.$