Question 1.10: An electric dipole with dipole moment 4 × 10 −9 C m is aligned at 30° with the direction of a uniform electric field of magnitude 5 × 10 4 N C −1 . Calculate the magnitude of the torque acting on the dipole.
Class 12 - Physics - Electric Charges And Fields Electric Charges And Fields Page-46
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Answered by
161
Hey mate!
Here's your answer!!
Electric dipole moment, p = 4 × 10−9 C m
Angle made by p with a uniform electric field, θ = 30°
Electric field, E = 5 × 104 N C−1
Torque acting on the dipole is given by the relation, τ = pE sinθ
= 4×10^-9×5×10^4×sin30
= 20×10^-5×1/2
=10^-4 Nm
Therefore, the magnitude of the torque acting on the dipole is 10−4 N m.
Here's your answer!!
Electric dipole moment, p = 4 × 10−9 C m
Angle made by p with a uniform electric field, θ = 30°
Electric field, E = 5 × 104 N C−1
Torque acting on the dipole is given by the relation, τ = pE sinθ
= 4×10^-9×5×10^4×sin30
= 20×10^-5×1/2
=10^-4 Nm
Therefore, the magnitude of the torque acting on the dipole is 10−4 N m.
Answered by
72
Torque acting on the dipole is given by
τ = PEsinΦ
Where P is dipole moment
E is the Electric field
Φ is the angle between dipole moment and electric field.
Given, P = 4 × 10⁻⁹ Cm
E = 5 × 10⁴ N/C
Φ = 30°
∴ τ = 4 × 10⁻⁹ × 5 × 10⁴ sin30°
= 4 × 5 × 10⁻⁵ × 1/2
= 10⁻⁴ Nm
Hence, torque acting on dipole is 10⁻⁴ Nm
τ = PEsinΦ
Where P is dipole moment
E is the Electric field
Φ is the angle between dipole moment and electric field.
Given, P = 4 × 10⁻⁹ Cm
E = 5 × 10⁴ N/C
Φ = 30°
∴ τ = 4 × 10⁻⁹ × 5 × 10⁴ sin30°
= 4 × 5 × 10⁻⁵ × 1/2
= 10⁻⁴ Nm
Hence, torque acting on dipole is 10⁻⁴ Nm
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