Math, asked by gamingush, 1 year ago

Question 1, A gardener has 1000 plants. He wants to plant these in such a way that the number of rows and the number of columns remain same. Find the minimum number plants he needs more for this.

Question 2, There are 500 children in a school, For a P.T. drill, they have to stand in such a way manner that the number of rows equal to the number of columns. How many children would be left out in this arrangement?
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Answers

Answered by hdewangan
9
1. If the number of rows and columns remains the same then the number should be in the form X^2. Since 1000 is not a perfect square number therefore we have to find out nearest perfect square numbers from 1000. 1024 is the nearest perfect square number from 1000 that's why he need 24 more plants.

2. For this we have to find the nearest perfect square number below 500. The nearest perfect square below 500 is 484 so 16 children left out in this arrangement.

gamingush: thanks bro, you solved the hardest question!!!
hdewangan: No need to say thanks buddy:)
hdewangan: We are here to help each other.
Answered by aarushmanglani
5

Answer:


Step-by-step explanation:

1. If the number of rows and columns remains the same then the number should be in the form X^2. Since 1000 is not a perfect square number therefore we have to find out nearest perfect square numbers from 1000. 1024 is the nearest perfect square number from 1000 that's why he need 24 more plants.


2. For this we have to find the nearest perfect square number below 500. The nearest perfect square below 500 is 484 so 16 children left out in this arrangement.


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