The length of the tangent to a circle from a point P, which is 25 cm away from the centre, is 24 cm. What is the radius of the circle.
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Let AP be a tangent drawn from P to a circle with Centre O such that AP = 24 cm & OB = 25 cm
We know that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
In right angled ∆OAP, OA ⟂ AP,
OP² = OA² + AP²
[By Pythagoras theorem]
25² = OA² + 24²
625 = OA² + 576
OA² = 625 - 576
OA² = 49
OA = √49
OA = 7 cm
Hence, the radius of the Circle is 7 cm.
HOPE THIS WILL HELP YOU...
We know that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
In right angled ∆OAP, OA ⟂ AP,
OP² = OA² + AP²
[By Pythagoras theorem]
25² = OA² + 24²
625 = OA² + 576
OA² = 625 - 576
OA² = 49
OA = √49
OA = 7 cm
Hence, the radius of the Circle is 7 cm.
HOPE THIS WILL HELP YOU...
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Here is your answer
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The shortest distance from point P to the circle is the length of x.
hypotenuse OP equals to
Therefore ,
=>
X = 6.5 - 2.5 = 4
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The shortest distance from point P to the circle is the length of x.
hypotenuse OP equals to
Therefore ,
=>
X = 6.5 - 2.5 = 4
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