Question 1 answer plzz
Attachments:
Answers
Answered by
0
In ΔABC,
right angled at C,
CD perpendicular to AB
To prove:- CD²= AD x DB
Proof:- CD perpendicular to AB
therefore ΔADC ~ ΔBDC
therefore AD/CD = CD/BD
=>CD² = AD x BD
right angled at C,
CD perpendicular to AB
To prove:- CD²= AD x DB
Proof:- CD perpendicular to AB
therefore ΔADC ~ ΔBDC
therefore AD/CD = CD/BD
=>CD² = AD x BD
Attachments:
adarshmishra092:
It's wrong
how is it wrong?
Similar questions