Question 1 Evaluate
(I) sin18 / cos72
(II) tan 26 / cot 64
(III) cos 48° − sin 42°
(IV)cosec 31° − sec 59°
Class 10 - Math - Introduction to Trigonometry Page 189
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Answered by
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Heya,
Here are the required solutions:-
iii)cos 48° - sin 42°
Here are the required solutions:-
iii)cos 48° - sin 42°
= cos (90°- 42) – sin 42°
= sin 42° - sin 42°
= 0
iv.) cosec 31° - sec 59°
= cosec (90° - 59°) – sec 59°
= sec 59° - sec 59°
= 0
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