Question 1: Find dy/dx : 2x + 3y = sin x
Class 12 - Math - Continuity and Differentiability
Answers
Answered by
4
differentiation of implicit function :
2x+3y = sinx
differentiating with respect to x
=2 + 3dy/dx = cosx { dy/dx(cosx) =1
=3dy/dx = cosx-2
=dy/dx = (cosx-2)/3
2x+3y = sinx
differentiating with respect to x
=2 + 3dy/dx = cosx { dy/dx(cosx) =1
=3dy/dx = cosx-2
=dy/dx = (cosx-2)/3
Answered by
6
★ DIFFERENTIATION ★
Given function to be differentiated :
2x + 3y = Sin x
d 2x / dx + d 3y / dx = d Sinx / dx
2 + 3dy/dx = Cosx
Hence , dy/dx = Cosx-2/3
It can be solved by using insertion of TRIGONOMETRIC and LOGARITHMIC functions too , but it'll result the same as above described
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Given function to be differentiated :
2x + 3y = Sin x
d 2x / dx + d 3y / dx = d Sinx / dx
2 + 3dy/dx = Cosx
Hence , dy/dx = Cosx-2/3
It can be solved by using insertion of TRIGONOMETRIC and LOGARITHMIC functions too , but it'll result the same as above described
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Similar questions