Question

Question 1: Find dy/dx : 2x + 3y = sin x

Class 12 - Math - Continuity and Differentiability

Answer 1

differentiation of implicit function :
2x+3y = sinx
differentiating with respect to x
=2 + 3dy/dx = cosx { dy/dx(cosx) =1
=3dy/dx = cosx-2
=dy/dx = (cosx-2)/3

Answer 2

★ DIFFERENTIATION ★

Given function to be differentiated :

2x + 3y = Sin x

d 2x / dx + d 3y / dx = d Sinx / dx

2 + 3dy/dx = Cosx

Hence , dy/dx = Cosx-2/3

It can be solved by using insertion of TRIGONOMETRIC and LOGARITHMIC functions too , but it'll result the same as above described

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