Question 2: Find dy/dx : 2x + 3y = sin y
Class 12 - Math - Continuity and Differentiability
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Answered by
12
★ DIFFERENTIATION ★
By applying chain rule at a point and by using concepts involved in solving implicit functions aslike , we can obtain the value of dy/dx
d 2x /dx + d 3y /dx = d Sin y /dx
2 + 3 dy/dx = Cos y (dy/dx)
Cosy ( dy/dx) = 2 + 3 dy/dx
Cosy ( dy/dx ) - 3 dy/dx = 2
dy/dx [ Cosy - 3 ] = 2
dy/dx = 2/Cos y - 3
★✩★✩★✩★✩★✩★✩★✩★✩★✩★
By applying chain rule at a point and by using concepts involved in solving implicit functions aslike , we can obtain the value of dy/dx
d 2x /dx + d 3y /dx = d Sin y /dx
2 + 3 dy/dx = Cos y (dy/dx)
Cosy ( dy/dx) = 2 + 3 dy/dx
Cosy ( dy/dx ) - 3 dy/dx = 2
dy/dx [ Cosy - 3 ] = 2
dy/dx = 2/Cos y - 3
★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Answered by
11
Differentiation of Implicit function
Refer to the attachment
Sorry :: In place of cosx there will be cosy
Refer to the attachment
Sorry :: In place of cosx there will be cosy
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