Question

Question 1

find the curved surface area or lateral surface area of a cylinder whose height is 14 cm and the radius is 10 cm.





Question 2

find the volume of a cylinder can of height 21 cm and base radius 8 cm​

Answer 1

Answer:

Step-by-step explanation:

Curved surface area of cylinder =2πrh

Given, r=14 cm, π=  

7

22

​  

 and h=10 cm

Curved surface area of cylinder =2×  

7

22

​  

×14×10

=44×2×10

=880 cm

2

The volume of cylindrical can is 4224 cubic cm

Step-by-step explanation:

Height of cylindrical can = 21 cm

Radius of cylindrical can = 8 cm

Volume of cylindrical can =  

Volume of can =  

Volume of can =

Hence The volume of cylindrical can is 4224 cubic cm

#Learn more:

In a cylindrical container , the base radius is 8 cm . If the height of the water level is 20 cm , find the volume of the water in the container

Answer 2

$\large\underline{ \underline{ \sf \maltese{ \: Question\: 1:- }}}$

• Find the curved surface area or lateral surface area of a cylinder whose height is 14 cm and the radius is 10 cm.

$\large\underline{ \underline{ \sf \maltese{ \: Given:- }}}$

• Radius ( r ) = $\sf\green{ 10cm}$
• Height ( h ) = $\sf\green{ 14cm}$

$\large\underline{ \underline{ \sf \maltese{ \: To\: Find:- }}}$

• The Curved surface Area or Lateral surface Area of a cylinder

$\large\underline{ \underline{ \sf \maltese{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Lateral\: Surface \:Area \: = \:2\pi \: radius \:\times \: height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 2 \: \times \: \frac{22}{7} \: \times \: 10 \: \times \: 14 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 2 \: \times \: \frac{22}{ \cancel \red7} \: \times \: 10 \: \times \: \cancel {\red{14} } }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 2 \: \times \: 22 \: \times \: 10 \: \times \: 2 }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ Lateral\: Surface \:Area\: = \: 880sq.cm }}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\underline{ \underline{ \sf \maltese\green{ \: Question\: 2:- }}}$

• Find the volume of a cylinder can of height 21 cm and base radius 8 cm

$\large\underline{ \underline{ \sf \maltese\green{ \: Given:- }}}$

• Radius ( r ) = $\sf\blue{ 8cm}$
• Height ( h ) = $\sf\blue{ 21cm}$

$\large\underline{ \underline{ \sf \maltese\green{ \: To\: Find:- }}}$

• Volume of the cylinder

$\large\underline{ \underline{ \sf \maltese\green{ \: Solution:- }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Volume \: of \: Cyclinder \: = \:\pi \:(radius)^{2} \: \times \: height }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \: \frac{22}{7} \: \times \: {(8)}^{2}\: \times \: 21 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \: \frac{22}{7} \: \times8 \: \times \: 8 \: \times \: 21 }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ \: \frac{22}{ \cancel \red7} \: \times \: 8 \: \times \: 8\: \times \: \cancel {\red{21} } }}$

$\qquad \quad {:} \longrightarrow \sf{\sf{ 2 \: \times \: 22 \: \times \: 8\: \times \: 8 \: \times \: 3 }}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{ Volume \: of \: Cyclinder\: = \: 4224cu.cm }}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

Answer 1:-

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ L.S.A \: of \: Cyclinder \: = \underline{\underline{ 880sq.cm}}}\\\end{gathered}\end{gathered}$

Answer 2:-

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Volume\: of \: Cyclinder \: = \underline{\underline{ 4224cu.cm}}}\\\end{gathered}\end{gathered}$

━━━━━━━━━━━━━━━━━━━━━━━━━