Question

Question 1:
Find the zeroes of the following quadratic polynomials and verify the relationship
between the zeroes and the coefficients
(i) x^2-2^x-8
(ii) 4s^2 - 4s +1
(iii) 6x^2 -3 - 7x​

Answer 1

by this process you can easily solve your question

Answer 2

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Correct Question:-

Find the zeroes of the following quadratic polynomials and verify the relationship

between the zeroes and the coefficients.

• $→ {x}^{2} - 2x - 8$
• $→4 {s}^{2} - 4s + 1$
• $→6 {x}^{2} - 7x - 3$

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Answer:-

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Step by step explanation:-

(i)

${x}^{2} - 2x - 8$

Ans:-

First find zeros by spelling the middle term

$→ {x}^{2} - 2x - 8 \\ \\ → {x}^{2} - (4 - 2)x - 8 \\ \\ →x(x - 4) + 2(x - 4) \\ \\ →(x - 4)(x + 2)$

So, zeros are

$x = 4 - - - - \alpha$

$x = - 2 - - - - - \beta$

Verification of relationship

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Formula used :-

Sum =

$\alpha + \beta = \frac{cofficient \: of \: x}{cofficint \: of \: {x}^{2} }$

Product =

$\alpha \beta = \frac{constant \: term}{cofficient \: of \: {x}^{2} }$

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Now let the equation be

$a {x}^{2} + b x + c$

So,

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See in attachment