Question

Question 1 In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate.
Show that these observations are in agreement with the law of conservation of mass. Sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water

Class 9 - Science - Atoms and Molecules Page 32

Answer 1

Heya !

Here is your answer ============================================================================

>> Mass of sodium carbonate = 5.3 g (given)

Mass of ethanoic acid = 6 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Mass of Carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Now, total mass before the reaction = (5.3 + 6) g
= 11 . 3 g

And, total mass after the reaction = (8.2 + 2.2 + 0.9 ) g

= 11.3 g

total mass before the reaction = total mass after the reaction.

Hence, the given observations are in agreement with the law of conservation of mass.

Hope it helps !!! : )

Answer 2

Heya,

Given,

5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. 

5.3 g Na2 Co3 + 6 g  ethanoic acid = 2.2 g CO2 +0.9 H2O + 8.2 sodium ethonate 

L.H.S (Mass of reactants)

⇒ 5.3 + 6 = 11.3

R.H.S (Mass of products)

⇒ 2.2 + 0.9 +8.2= 11.3

⇒L.H.S = R.H.S

Therefore these are in agreement with the law of conservation of mass.

Hope it helps u.......