Question 2 Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?
Class 9 - Science - Atoms and Molecules Page 33
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Answered by
123
Heya !
Here is your answer ================================================================================
>> Here we have been given that hydrogen and oxygen always combine in the fixed ratio of 1 : 8 by mass. This means that :
1 g of hydrogen has require = 8 g of oxygen gas
So, 3 g of hydrogen gas require = 8 × 3 g of oxygen gas
= 24 g of oxygen gas
Thus, 24 g of oxygen gas would be required to react completely with 3 grams of hydrogen gas.
Hope it helps !!! : )
Here is your answer ================================================================================
>> Here we have been given that hydrogen and oxygen always combine in the fixed ratio of 1 : 8 by mass. This means that :
1 g of hydrogen has require = 8 g of oxygen gas
So, 3 g of hydrogen gas require = 8 × 3 g of oxygen gas
= 24 g of oxygen gas
Thus, 24 g of oxygen gas would be required to react completely with 3 grams of hydrogen gas.
Hope it helps !!! : )
Answered by
38
Answer:
- It is given that the ratio of hydrogen and oxygen by mass to form water is 1:8.
- Then, the mass of oxygen gas required to react completely with 1 g of hydrogen gas is 8 g.
- Therefore, the mass of oxygen gas required to react completely with 3 g of hydrogen gas is 8 × 3 g = 24 g.
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