Question

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(1- iota ) ^4


(1/3+3 iota)^3


(1-iota )-(-1+iota 6)

Answer 1

ĀNSWĒR ⏬⏬

1.)-4,0

2.)242/27,26

3.)2 , -7


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#Nishu HarYanvi ♥

Answer 2

Answer:

Step-by-step explanation:

Iota's power 3 is -ve iota.

Let iota be represented by i

i=(-1)^1/2

i^2=[(-1)^1/2]^2=-1

i^3=i^2×i=-1×i (as i^2=-1)

i^3=-i

Iota is square root of minus 1 means √-1 .

So its cube will simply be

(√-1)^3= -√-1

Simply minus iota.

Thank You...