Math, asked by BrainlyHelper, 1 year ago

Question 1: Prove 3sin¯¹ x = sin¯¹ (3x – 4x³), x ∈ [ -1/2, 1/2 ]

Class 12 - Math - Inverse Trigonometric Functions

Answers

Answered by BigSmoke
4
Put x= sin Q
Q = sin inverse x - - - - - - - - 1

The equation becomes,
Sin inverse ( 3sinQ - 4 sin cube Q)

As 3sinQ - 4SincubeQ = Sin3Q then,

Sin inverse(sin3Q) = 3Q = 3sin inverse x(from 1)

Hope you get your answer.
Answered by Anonymous
0

Step-by-step explanation:

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Sin inverse ( 3sinQ - 4 sin cube Q)

As 3sinQ - 4SincubeQ = Sin3Q then,

Sin inverse(sin3Q) = 3Q = 3sin inverse

x(from 1)

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