Question 1: Prove 3sin¯¹ x = sin¯¹ (3x – 4x³), x ∈ [ -1/2, 1/2 ]
Class 12 - Math - Inverse Trigonometric Functions
Answers
Answered by
4
Put x= sin Q
Q = sin inverse x - - - - - - - - 1
The equation becomes,
Sin inverse ( 3sinQ - 4 sin cube Q)
As 3sinQ - 4SincubeQ = Sin3Q then,
Sin inverse(sin3Q) = 3Q = 3sin inverse x(from 1)
Hope you get your answer.
Q = sin inverse x - - - - - - - - 1
The equation becomes,
Sin inverse ( 3sinQ - 4 sin cube Q)
As 3sinQ - 4SincubeQ = Sin3Q then,
Sin inverse(sin3Q) = 3Q = 3sin inverse x(from 1)
Hope you get your answer.
Answered by
0
Step-by-step explanation:
Sin inverse ( 3sinQ - 4 sin cube Q)
As 3sinQ - 4SincubeQ = Sin3Q then,
Sin inverse(sin3Q) = 3Q = 3sin inverse
x(from 1)
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