Question 2: Prove 3cos¯¹ x = cos¯¹ (4x³ – 3x), x ∈ [1/2,1]
Class 12 - Math - Inverse Trigonometric Functions
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To prove: 3−1 = -¹
(4
³ − 3), ∈ [
1
/2
, 1].
Let cos-¹x = θ, then x = cos θ.
We have,
RHS
cos-¹ (4x ³-3x) = cos-¹(4cos³θ-3cosθ)
= cos-¹(cos 3θ) = 3θ = 3cos-¹x
= LHS
Let cos-¹x = θ, then x = cos θ.
We have,
RHS
cos-¹ (4x ³-3x) = cos-¹(4cos³θ-3cosθ)
= cos-¹(cos 3θ) = 3θ = 3cos-¹x
= LHS
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