Question

[ Question ]

1.) Using quadratic formula , solve for 'x'

9x² – 9(a + b)x + (2a² + 5ab + 2b²) = 0
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Answer 1

Answer:

In any quadratic equation, quadratic formula is the direct method if any other method does now work.

The roots X1 and X2 of a quadratic equation ax² + bx + c is found by =

X1 = (b² + (√b² - 4ac))/2a

X2 = (b² - (√b²- 4ac))/2a

The square root is for the entire expression b² - 4ac

In your equation,

a = coefficient of x² i.e. 9

b = coefficient of x i.e. -9(a+b)

c = constant i.e. 2a² + 5ab + 2b²

So the roots will be =

[[-9(a+b)]² ± (√((-9(a+b))² - 4(9)(2a² + 5ab + 2b²)]/2a

Since I've put the ± sign together, you'll get two answers and they'll be the two roots.

This is ur answer mate

Hope this helps