Math, asked by petitboy47, 6 months ago

Question 1- What is the sum ( in RS) which when divided among X Y Z in the
proportion 3:5:7 provides rupees 8000 more to Z then what it would have done to him
when the proportion is 11 : 15 : 19?

Answers

Answered by hydrogenshine1
54

Answer:

The correct answer is 180000 rupees.

Step-by-step explanation:

Let the sum=x

The dividend for z=7x/(7+3+5)=7x/15 for initial distribution

The dividend for z=19x/(19+11+15)=19x/45 for new distribution

From the given condition we get

7x/15–19x/45=8000

2x=8000×45

x=180000

PLEASE MARK AS BRAINLIEST ANSWER

DON'T FORGET TO PRESS ON THANKS IF YOU FIND IT HELPFUL

Answered by qwvilla
4

Question :

What is the sum ( in RS) which when divided among X Y Z in the proportion 3:5:7 provides rupees 8000 more to Z than what it would have done to him when the proportion is 11 : 15 : 19?

Answer :

The sum of money is Rs.180000.

Given :

Ratio of sum of money divided among X , Y and Z = 3:5:7

Amount of money which Z receives more than what it would have done to him when the proportion is 11 : 15 : 19 = Rs.8000

To find :

The total sum of money

Solution :

Let the sum of money be Rs. x

Sum of ratio = 3 + 5 + 7

= 15

Hence, Z's share = 7/15 of x

= 7x/15

Sum of ratio in 11 : 15 : 19 = 11 + 15 + 19

= 45

Here, Z's share = 19/45 of x

= 19x/45

According to the problem,

=> 7x/15 = 19x/45 + 8000

=> 7x/15 - 19x/45 = 8000

=> (3*7x - 19x)/45 = 8000

=> (21x - 19x)/45 = 8000

=> 2x/45 = 8000

=> 2x = 8000 × 45

=> 2x = 360000

Or, x = 360000/2

Hence, x = 180000

Therefore, the sum of money is Rs.180000.

#SPJ3

Similar questions