Question

Question 10: Differentiate the following w.r.t. x: cos (log x + e^x), x > 0

Class 12 - Math - Continuity and Differentiability

Answer 1

Differentiating with respect to x the above expression we get,

dy/dx = - sin(logx + e^x) ( 1/x + e^x. 1)

Hope you get your answer.

Answer 2

Refer to the attachment.
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Formulas used :-
•d/dx(logx) = 1/x
•d/dx(xⁿ) = nxⁿ-¹
•d/dx(e^x) = e^x
•d/dx(cosx) = -sinx
•d/dx(sinx) = cosx
×××Differentiation using chain rule ×××