Question 9: Differentiate the following w.r.t. x: cos x/log x , x > 0
Class 12 - Math - Continuity and Differentiability
Answers
Answered by
2
Y= cosx logx^-1
dy/dx = - sinx. 1/logx + cosx(-1)logx^-2.1/x
dy/dx = - sinx/logx - cosx/logx^2.1/x
Hope you get your answer to.
dy/dx = - sinx. 1/logx + cosx(-1)logx^-2.1/x
dy/dx = - sinx/logx - cosx/logx^2.1/x
Hope you get your answer to.
Answered by
0
Refer to the attachment.
----------------------------
Formulas used :-
•d/dx(logx) = 1/x
•d/dx(cosx) = -sinx
•d/dx(sinx) = cosx
×××Differentiation using division rule ×××
----------------------------
Formulas used :-
•d/dx(logx) = 1/x
•d/dx(cosx) = -sinx
•d/dx(sinx) = cosx
×××Differentiation using division rule ×××
Attachments:
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