Question

Question 8: Differentiate the following w.r.t. x: log (log x), x > 1

Class 12 - Math - Continuity and Differentiability

Answer 1

Differentiating the above expression we get,

dy/dx = 1/logx × 1/x

Hope you get your answer.

Answer 2

let y = log(logx)

Now using chain rule

dydx = 1/logx × 1/x { d/dx(logx) = 1/x