Question 10 If 17 th term of an A.P. exceeds its 10 th term by 7. Find the common difference.
Class 10 - Math - Arithmetic Progressions Page 106
Answers
Answered by
2
given that
a+16d-(a+9d)=7
a+16d-a-9d =7
7d=7
d=7/7=1
therefore common difference=1
a+16d-(a+9d)=7
a+16d-a-9d =7
7d=7
d=7/7=1
therefore common difference=1
Answered by
3
AP ( Arithmetic progression). A list of numbers a1, a2, a3 ………….. an is called an arithmetic progression.
General term or nth term of A.P
General term or nth term of A.P
The general term or nth term of A.P is given by an = a + (n – 1)d,
where a is the first term, d is the common difference and n is the number of term.
-----------------------------------------------------------------------------------------------------
Solution:
We know that,
For an A.P., an = a + (n − 1) d
a17 = a + (17 − 1) d
a17 = a + 16d
Similarly, a10 = a + 9d
It is given that
a17 − a10 = 7
(a + 16d) − (a + 9d) = 7
a- a +16d -9d =7
7d = 7
d = 1
Hence the common difference is 1.
---------------------------------------------------------------------------------------------------
hope this will help you......
Similar questions