Question

Question 11 Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54 th term?

Class 10 - Math - Arithmetic Progressions Page 106

Answer 1

let the required term be nth term
54th term = a +(n-1)d
 = 3 + 53x12 = 3 + 636 = 639
therefore 132 + 639 = 771 will be the nth term.
771 = 3 + (n-1)12
768/12 +1 = n
therefore n = 64 +1 = 65
therefore the 65th term will be 132 more than the 54th term.... ANSWER


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Answer 2

a = 3
n = 54
d = 12

we know that

a + ( n - 1 ) d

= 3 + ( 54 - 1 ) 12

= 3 + 53 × 12

= 3 + 636

= 639

Now
132 + 639 = 771

771 = 3 + (n - 1) 12

768/12 + 1 = n

64 + 1 = n

n = 65

Therfore 65th term term 132 more than 54th term