Question

Question 11.4 Consider the compounds, BCl3 and CCl4. How will they behave with water? Justify.

Class XI The p-Block Elements Page 323

Answer 1

BCl3 is an electron deficient molecule . it easily accepts a pair of electron from water and hence, BCl3 undergoes Hydrolysis to form boric acid (H3BO3) and HCl.

BCl3 + 3H2O --->H3BO3 + 3HCl .

CCl4 is an electron precise molecule having absence of d- orbitals in C-atom and hence, it neither accepts nor donates a pair of electrons . thus, CCl4 doesn't undergo hydrolysis in water.

Answer 2

Answer:

1) the boron family shows 2 oxidation state +1 and +3 and carbon family shows +4 oxidation state

Explanation:

the increase order of +1 state of boron family is

B<Al<Ga<In<Tl

the increase order of +4 state of carbon family is

C<Si<Ge<Sn<Pb

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