Question 11 :
(a) The sum of 3rd and 11th terms of an A.P. is 34. Find the sum of its 13 term .
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Step-by-step explanation:
We know that
third term = a+2d----------a
and
11th term = a+10d---------b
now
a+b = 2a+12d = 34--------(given)
now sum of 13 terms is
Sn = S13 = 13/2×[2a+12d]
S13 = 13/2×34---------[2a+12d = 34]
therefore S13 = 13×17=221 Answer
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