question 11 and 12 plzzz hurry up
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ans.11) As CD is parallel to EF
angle B + angle C = 180
2x + 7x = 180
9x = 180
x= 20
therefore, angle B = 2x = 40
angle C = 7x = 140
As AB is parallel to CD,
angle A + angle B = 180
angle A + 40 = 180
angle A = 140
ans.12) ABP & ACQ forms a line.
Therefore,
angle ABC + anglePBC = 180......(1)
therefore,
angle ACB + angleQCB = 180......(2)
So, (1) & (2) equation show
angle ABC is greater than angle ACB,
therefore, AC is greater than AB
{side opposite to equl sides are equal}
angle B + angle C = 180
2x + 7x = 180
9x = 180
x= 20
therefore, angle B = 2x = 40
angle C = 7x = 140
As AB is parallel to CD,
angle A + angle B = 180
angle A + 40 = 180
angle A = 140
ans.12) ABP & ACQ forms a line.
Therefore,
angle ABC + anglePBC = 180......(1)
therefore,
angle ACB + angleQCB = 180......(2)
So, (1) & (2) equation show
angle ABC is greater than angle ACB,
therefore, AC is greater than AB
{side opposite to equl sides are equal}
anshul6169:
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