Question

Question 11.
From the sum of 2x2 + 3xy - 5 and 7 + 2xy - x? subtract 3xy + x2 -2.​

Answer 1

Step-by-step explanation:

= 2x² + 3xy - 5 + (7 + 2xy -x)

= 2x² + 3xy - 5 + 7 + 2xy - x

= 2x² + 5xy + 2 - x

subtraction..

= 2x² + 5xy + 2 - x - (3xy + x² - 2)

= 2x² + 5xy + 2 - x - 3xy - x² + 2

= x² + 2xy + 4 - x

Answer 2

Given,

Three equations are given 2x²+ 3xy - 5, 7 + 2xy - x and 3xy + x² - 2.

To find,

From the sum of 2x²+ 3xy - 5 and 7 + 2xy - x subtract 3xy + x² -2.

Solution,

First, we have to add the equation 2x²+ 3xy - 5 and 7 + 2xy - x on addition we would get,

⇒   (2x²+ 3xy - 5) +  (7 + 2xy - x)

⇒   2x² + (3xy + 2xy) + (-5 + 7)  -x

⇒   2x²  + 5xy + 2 -x.

Therefore the addition of 2x²+ 3xy - 5 and 7 + 2xy - x is 2x² + 5xy + 2 -x.

Now, subtract 3xy + x² - 2. from 2x²  + 5xy + 2 -x.

⇒   2x²  + 5xy + 2 -x - ( 3xy + x² - 2)

⇒   2x²  + 5xy + 2 -x - 3xy -x² +2

⇒   x² + 2xy -x +4

Hence, the final answer is x² + 2xy -x +4.