Question 11 please solve it
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Last Length (L) = Initial Length (L) + Total Length
Tension in the wire will be the difference between body weight and liquid (oil).
T = MG - ρgV (1)
here
I have mass of metal, ρ is the density of oil and the amount of V metal is
A small length segment will be given as the length of DX
E = tdx / airy
where
DX is a small length segment, A is the area of cross-section and Y is the Yoga modulus.
So, (1)
E = T (DX / AV) = (MG - ρgV) (DX / AV)
Or
E = (MG - ρgV) (1 / airy). dx
Thus, the total length can be calculated by integrating the entire length of the wire.
So,
E = (MG - ρgV). (1 / AY). L
We can calculate the expansion by replacing the appropriate values and then increasing the final length
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