Question 12.25 Why is nitric acid added to sodium extract before adding silver nitrate for testing halogens?
Class XI Organic Chemistry : Some Basic Principles and Techniques Page 363
Answers
Answered by
24
Hi
Here is your answer,
Sodium extract is boiled with nitric acid to decompose NaCN and Na₂S if present.
NaCN + HNO₃ ------> NaNO₃ + HCN ↑
Na₂S + 2HNO₃ -------> 2NaNO₃ + H₂S ↑
If cyanide and sulphide are not removed, they will react with AgNO₃ and hence, will interfere with the silver nitrate test for halogens.
NaCN + AgNO₃ --------> AgCN + NaNO₃
(white ppt.)
Na₂S + 2AgNO₃ ---------> Ag₂S + 2NaNO ₃
( black ppt.)
Here is your answer,
Sodium extract is boiled with nitric acid to decompose NaCN and Na₂S if present.
NaCN + HNO₃ ------> NaNO₃ + HCN ↑
Na₂S + 2HNO₃ -------> 2NaNO₃ + H₂S ↑
If cyanide and sulphide are not removed, they will react with AgNO₃ and hence, will interfere with the silver nitrate test for halogens.
NaCN + AgNO₃ --------> AgCN + NaNO₃
(white ppt.)
Na₂S + 2AgNO₃ ---------> Ag₂S + 2NaNO ₃
( black ppt.)
Answered by
9
If organic compound contains nitrogen and sulphur , the sodium extract on boiling with dilute HNO3 ( nitric acid) decomposes sodium cyanide or Sodium sulphide formed during fusion . NaCN + HNO3 ----> NaNO3 + HCN↑
Na2S + 2HNO3 -------> 2NaNO3 + H2S↑
if cyanide and sulphide ions are not decomposed , they will react with silver nitrate and hence, will interfere with the test .
NaCN + AgNO3 -----> AgCN(white ppt) + NaNO3
Na2S + 2AgNO3 -----> Ag2S (black ppt) + 2NaNO3
That's why nitric acid is added to sodium extract before adding of silver nitrate for testing halogens .
Na2S + 2HNO3 -------> 2NaNO3 + H2S↑
if cyanide and sulphide ions are not decomposed , they will react with silver nitrate and hence, will interfere with the test .
NaCN + AgNO3 -----> AgCN(white ppt) + NaNO3
Na2S + 2AgNO3 -----> Ag2S (black ppt) + 2NaNO3
That's why nitric acid is added to sodium extract before adding of silver nitrate for testing halogens .
Similar questions