question 12 i want answer
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answer to your question is 22
ananya52:
explain properly step by step
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x = √6+√5
1/x = 1/√6+√5
→ = 1/√6+√5 × √6-√5/√6-√5
→ = √6-√5/(√6²-√5²)
→ = √6-√5/6-5
→ 1/x = √6-√5
(x+1/x)² = x²+(1/x)² + 2(x)(1/x)
(√6+√5+√6-√5)² = x²+1/x²+2
(2√6)² = x²+1/x²+2
4(6) = x²+1/x²+2
x²+1/x² = 24-2
x²+1/x² = 22
Hope it helps,.......
1/x = 1/√6+√5
→ = 1/√6+√5 × √6-√5/√6-√5
→ = √6-√5/(√6²-√5²)
→ = √6-√5/6-5
→ 1/x = √6-√5
(x+1/x)² = x²+(1/x)² + 2(x)(1/x)
(√6+√5+√6-√5)² = x²+1/x²+2
(2√6)² = x²+1/x²+2
4(6) = x²+1/x²+2
x²+1/x² = 24-2
x²+1/x² = 22
Hope it helps,.......
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