Question 13: Find dy/dx : y = cos¯¹( 2x/ 1+x²), -1 < x < 1
Class 12 - Math - Continuity and Differentiability
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Answered by
4
y = cos-¹(2x/1+x²)
put x = tan∅
y = cos-¹(2tan∅/1+tan²∅)
y = cos-¹(sin2∅)
y = cos-¹(π/2-2∅)
y= π/2-2∅
y = π/2-2(tan-¹x)
Now differentiating w.r.t x
we get
dydx = -2/1+x²
put x = tan∅
y = cos-¹(2tan∅/1+tan²∅)
y = cos-¹(sin2∅)
y = cos-¹(π/2-2∅)
y= π/2-2∅
y = π/2-2(tan-¹x)
Now differentiating w.r.t x
we get
dydx = -2/1+x²
Answered by
7
Refer to the attachment.....
** Formula used **
♦ sin2x = 2tanx / 1 - tan²x
----------------------
Hope it helps..
** Formula used **
♦ sin2x = 2tanx / 1 - tan²x
----------------------
Hope it helps..
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